I'll call this next idea 'theory' for now--because I'm not too sure if this balanced circuit can/will return to zero volts quick enough after the circuit was unbalanced by either opening or shorting a section of the WSB part of the circuit. WSB means: wheat stone bridge, which is four resistors of the same value configured as shown. FWBR means: full-wave bridge rectifier, which takes all of the BEMF and rectifies it to positive--where it is stored up in the electrolytic capacitor as direct current voltage (Vdc).
What I'm intending to accomplish with this circuit is to end the need to closely regulate the BEMF so that it can be fed-back to the batteries directly, sans voltage/current regulators. In this type of asymmetrical circuit, the energy captured is twice that of the source voltage because the battery is in series with the coil.
You'll notice that there are two separate identical circuits in one being controlled by LED emiters and photo-transistors. What is being depicted as driver coils are actually two coils wound into one--where one lead of each coil is connected to the other and the other leads are used for the signal connections.
When the BEMF is released into the circuit, it is stored in the capacitor, where it is equal to the sum of the two batteries in series, which allows for direct feedback without any special regulating circuitry. Two 12V batteries are used in this circuit but each battery is used independently in its half of the circuit and they are only connected in series for the purpose of BEMF feedback.
All Q1 & Q2 transistors are PNP type intended for high speed switching of the gate connection of all Q3 & Q4 transistors--which are n-channel MOSFETs. I've left out a few components in this schematic e.g.: the draw-down resistor that holds the MOSFETs off when there is no + voltage signal at the gate.
When an emitter's light hits the reflective surface on the rotor, it will actuate the detector, thus causing whichever transistor to come on--which will in turn actuate its corresponding MOSFET.
Note: all of the blue and red lines, when butting up to a black line will form a connection, otherwise, wherever said lines cross, there is no connection.
You'll have to study both of these drawings to get a good understanding of what is happening in this particular system design. The black rectangle with the white stripes is the rotor laid out flat so as to get a better understanding of the reflective surface's interaction to the emitter/detector array. The rotor itself is black for reasons I'm sure y'all can understand.
This circuit produces one full phase, per two-pole rotor section, which is double that of my previous design, and so, just six rotor sections will produce a 6 phase motor... therefor a four phase motor, like I had previously shown and will re-post upon request, is half the size if this method is used.
Edited by Vanka Savolov, 11 May 2018 - 07:42 PM.